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una ferreteria compra 4 bobinas de cable de 200 metros cada una a 2 euros el metro ¿a cuanto debe vender el metro si quiere ganar 800 euros?

User FGreg
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2 Answers

3 votes

Final answer:

Para obtener una ganancia de 800 euros, la ferretería debe calcular primero el costo total de las bobinas y luego sumar la ganancia deseada. Dividiendo el ingreso total necesario por la cantidad total de metros, se encuentra que el metro de cable debe venderse a 3 euros.

Step-by-step explanation:

The question focuses on how to calculate the sales price per meter of cable to obtain a desired profit. First, we calculate the total cost of the cable reels. If 4 coils of 200 meters each are purchased and each meter costs 2 euros, then the total cost is:

Total cost = Number of coils × Meters per coil × Cost per meter

Total cost = 4 coils × 200 meters/coil × 2 euros/meter

Total cost = 1600 euros

Then, we add the desired profit of 800 euros to the cost to obtain the total income needed:

Total revenue needed = Total cost + Desired profit

Total income needed = 1600 euros + 800 euros

Total income needed = 2400 euros

Finally, we divide the total revenue needed by the total number of meters of cable to determine how much per meter of cable should be sold for:

Sales price per meter = Total income needed / Total number of meters

Sale price per meter = 2400 euros / (4 × 200 meters)

Sale price per meter = 2400 euros / 800 meters

Sale price per meter = 3 euros/meter

Therefore, the hardware store must sell the meter of cable for 3 euros to obtain a profit of 800 euros.

User Alternatex
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4.6k points
1 vote

Answer:

The selling price of meter of cable must be equal to 3 euros

Step-by-step explanation:

The question in English is

A hardware store buys 4 reels of cable of 200 meters each at 2 euros per meter. How much must the meter sell if you want to earn 800 euros?

we know that

The profit will be equal to the selling price minus the purchase price, all multiplied by the total meters of cable

Let

x -----> the selling price of the meter of cable

y -----> the purchase price of the meter of cable

N ----> the meters of cable

P ----> the profit

so


P=N(x-y)

we have

The total meters of cable N purchased is equal to


N=4(200)=800\ m


y=2\ euros\meter


P=800\ euros

substitute


800=800(x-2)

Solve for x

Simplify


1=(x-2)


x=2+1=3\ euros

therefore

The selling price of meter of cable must be equal to 3 euros

User Cheloute
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4.9k points