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Prove that a=v^2 /r​

Prove that a=v^2 /r​-example-1
User Myasia
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Step-by-step explanation:

Imagine a point moving about a circle with a speed of v. At time t = 0, the point is at the bottom of the circle. It has an initial velocity u pointing to the right. The horizontal component is uₓ = v, and the vertical component is uᵧ = 0.

After a short time t, the point has moved a small angular distance of θ. At this position, the horizontal component of the velocity is vₓ = v cos θ, and the vertical component is vᵧ = v sin θ.

When θ is very small, v cos θ ≈ v, and v sin θ ≈ v θ.

The linear acceleration is the change in horizontal velocity over time:

aₓ = (vₓ − uₓ) / t

aₓ = (v − v) / t

aₓ = 0

And the centripetal acceleration is the change in vertical velocity over time:

aᵧ = (vᵧ − uᵧ) / t

aᵧ = (v θ − 0) / t

aᵧ = v θ / t

The time is the distance (in this case, the arc length) divided by speed:

t = s / v

t = rθ / v

Substituting:

aᵧ = v θ / (rθ / v)

aᵧ = v θ × (v / (rθ))

aᵧ = v² / r

User Jahjajaka
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