Question

What is the slope of a line perpendicular to the line y=8x+1

Answer 1

Slope of a line perpendicular to the line y=8x+1 is
`(-1)/(8)`

Solution:

Given y=8x+1

The slope - intercept form equation of line is given as

y = mx + c --- eqn 1

Where m is the slope of the line.

The coefficient of “x” is the value of slope of the line.

"c" is the y – intercept which is the value of y at the point where the line crosses the y-axis

From question, given that y = 8x + 1

Comparing the given equation y=8x+1 with equation 1, we get

m = 8 and c = 1

The equation of a perpendicular line to y=8x+1 must have a slope that is the negative reciprocal of the original slope.

`\mathrm{m}_{\text {reciprocal }}=-(1)/(8)`

Hence the slope of the line perpendicular to the line y=8x+1 is
`(-1)/(8)`