Question

Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 1.84 m away from a waterfall 0.251 m in height, at what minimum speed must a salmon jumping at an angle of 38.3 ◦ leave the water to continue upstream? The acceleration due to gravity is 9.81 m/s 2 .

Answer 1

4.73 m/s

Step-by-step explanation:

R=1.84 m

H=0.251 m

∅=38.3°

For Horizontal Motion

aₓ=0 uₓ=ucos∅

x=uₓt+
`(1axt^(2) )/(2)`

R=ucos∅*t+0

1.84=ucos(38.3)*t

t=
`(2.344)/(u)`

For Vertical Motion

Y=Uy*t+
`(1ayt^(2) )/(2)`

By putting value

0.251=usin∅(
`(2.344)/(u)`)-(
`(1)/(2)g *((2.344)/(u) )^(2)`)

0.251=sin(38.3)(
`\frac{2.344}`)-(
`(1)/(2)g *((2.344)/(u) )^(2)`)

0.251=1.452-
`(83.057)/(u^(2) )`

u²=22.41

u=4.73 m/s