90.9k views
0 votes
Need help ASAP!!

A stadium has 49,000 seats. Seats sell for ​$30 in Section​ A, ​$24 in Section​ B, and ​$18 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,246,800 from each​ sold-out event. How many seats does each section​ hold?

User Mmed
by
7.6k points

1 Answer

7 votes

Answer:

  • A: 24,500
  • B: 11,800
  • C: 12,700

Explanation:

Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.

The revenue from those seats is, ...

24,500×$30 = $735,000

so the revenue from B and C seats is ...

$1,246,800 -735,000 = $511,800

__

We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...

24b +18(24500-b) = 511800

6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms

b = 70,800/6 = 11,800 . . . . . . . seats in B section

24,500 -11,800 = 12,700 . . . . . seats in C section

There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.

User Walfie
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories