Question

Need help ASAP!!

A stadium has 49,000 seats. Seats sell for ​$30 in Section​ A, ​$24 in Section​ B, and ​$18 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,246,800 from each​ sold-out event. How many seats does each section​ hold?

Answer 1

• A: 24,500
• B: 11,800
• C: 12,700

Explanation:

Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.

The revenue from those seats is, ...

24,500×$30 = $735,000

so the revenue from B and C seats is ...

$1,246,800 -735,000 = $511,800

__

We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...

24b +18(24500-b) = 511800

6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms

b = 70,800/6 = 11,800 . . . . . . . seats in B section

24,500 -11,800 = 12,700 . . . . . seats in C section

There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.