Question

Need help ASAP!!

A stadium has 46,000 seats. Seats sell for ​$42 in Section​ A, ​$24 in Section​ B, and ​$18 in Section C. The number of seats in Section A equals the total number of seats in Sections B and C. Suppose the stadium takes in ​$1,467,600 from each​ sold-out event. How many seats does each section​ hold?

Answer 1

The answer to your question is:

A = 23000

B = 14600

C = 8400

Explanation:

Data

A = $42

B = $24

C = $18

A = B + C

Equations

42A + 24B + 18C = 1,467,600

A + B + C = 46,000

Process

A + A = 46,000

2A = 46000

A = 23000

B + C = 23000

B = 23000 - C

42(23000) + 24(23000 - C) + 18C = 1,467,600

966000 + 552000 - 24C + 18C = 1467600

-6C = -50400

C = 8400

B = 23000 - 8400

B = 14600