Question

Ball A is attached to one end of a rigid massless rod, while an identical ball B is attached to the center of the rod, as shown in the figure. Each ball has a mass of m =

0.450 kg, and the length of each half of the rod is L = 0.420 m. This arrangement is held by the empty end and is whirled around in a horizontal circle at a constant rate,
so that each ball is in uniform circular motion, Ball A travels at a constant speed of VA = 5.10 m/s. Find (a) the tension of the part between A and B of the rod and (b)
the tension of the part between B and the empty end.

Answer 1

Step-by-step explanation:

From the given data angular speed is equal to

w=VA/RA

w=5.1/2*0.42

=6.07 rad/s

a) TAB=m*a

=m*(RA)*(
`w^(2)`)

=0.45*(2*0.42)(
`6.07^(2)`

=13.92 N

b) TBO=TAB+m*a

=13.92+0.45*0.42*
`6.07^(2)`

=20.88 N