Answer:
(a) When 400 donuts are made daily the company's profits is 250 dollars.
(b) The Company should produce 950 donuts daily in order to maximize its profits.
Explanation:
Profit function P(x) = - 0.001 x² + 1.9x - 350
where p is the profit and x is the quantity of donuts made daily.
(a) If x = 400, the company's profit is:
P(x) = - 0.001 x² + 1.9x - 350
= - 0.001 (400)² + 1.9(400) - 350
=
![-(160000)/(1000) + (7600)/(10) - 350](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d9cck1thw9oc7redemoxkb5fjh3u5xw0mw.png)
= - 160 + 760 - 350
= 760 - 510
= 250
(b) The profit of a firm is maximum when MR = MC or MR - MC = 0 which is also known as break even point. In other words, at break-even point the profit function equals to zero. ∴,
![(d)/(dx) P(x) = (d)/(dx)(- 0.001x^(2) + 1.9x - 350)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xdrt71en0aohmx96ln4tquzwv964udawb4.png)
![(d)/(dx)(- 0.001x^(2) + 1.9x - 350) = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rrqwmq4nm2tjnqjq87voglyetv0kz8ugv4.png)
![- 0.002 x + 1.9 = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ygepx515rwn0h3dxggzkcn2y8jm6nnb4ry.png)
![x = (1.9)/(0.002)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/erq40y68iz3n8ntmckb2cnggdgd4f5ek1q.png)
![x = 950](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iqeeh3rijq91nn379aqusxm3dcjnihghgu.png)
Therefore, the Company should produce 950 donuts daily in order to maximize its profits.