Question

Find the magnitude of the vector:​

Answer 1

Explanation:

Answer 2

`\large\boxed{|\overrightarrow{CD}|=3√(61)}`

Explanation:

The formula of a magnitude of vector:

`|\overrightarrow{AB}|=√((x_2-x_1)^2+(y_2-y_1)^2)`

where

`A(x_1,\ y_1),\ B(x_2,\ y_2)`

We have:

`C(10,\ 10),\ D(-8,\ -5)`

Substitute:

`|\overrightarrow{CD}|=√((-8-10)^2+(-5-10)^2)\\\\|\overrightarrow{CD}|=√((-18)^2+(-15)^2)\\\\|\overrightarrow{CD}|=√(324+225)\\\\|\overrightarrow{CD}|=√(549)\\\\|\overrightarrow{CD}|=√((9)(61))\\\\|\overrightarrow{CD}|=√(9)\cdot√(61)\\\\|\overrightarrow{CD}|=3√(61)`