For this case we have to by definition:
If two lines are parallel then their slopes are equal.
If two lines are perpendicular then the product of their slopes is equal to -1.
We have the following equations:
![4y-12 = 3x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ufzxcagubu7yckij1wxgl7eg6lw1k9jxle.png)
We manipulate the equation to convert it into the slope-intersection form
![y = mx + b](https://img.qammunity.org/2020/formulas/mathematics/high-school/fc4cgm6covys37zv2opmmp9ps4jxyjepvh.png)
Where:
m: It's the slope
y: It is the cut-off point with the y axis.
So:
![4y = 3x + 12\\y = \frac {3} {4} x + \frac {12} {4}\\y = 0.75x + 3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xblsdn15ra0cembfse1ya6z8fsu94kl7o8.png)
From the second equation given we have:
![2y-1.5x = -14](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nhm57hmm7wd8d5liq25fi4r9dr0e1jarp9.png)
We manipulate:
![2y = 1.5x-14\\y = \frac {1.5} {2} x- \frac {14} {2}\\y = 0.75x-7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/agm87t8j06qjk85bofxnnhyxrueuz4ktjf.png)
It is observed that the slopes are equal, so the lines are parallel,
ANswer:
The lines are parallel.