Question

The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = 1/4 (x – 8). What is the slope-intercept form of the equation for this line?

y = y = 1/4x - 12.x – 12
y = y = 1/4x - 4.x – 4
y = y = 1/4x + 2.x + 2
y = y = 1/4x + 6.x + 6

Answer 1

`\large\boxed{y=(1)/(4)x+2}`

Explanation:

The slope-intercept form of an equation of a line:

`y=mx+b`

m - slope

b - y-intercept

We have the equation in the point-slope form.

`y-4=(1)/(4)(x-8)`

Convert to the slope-intercept form:

`y-4=(1)/(4)(x-8)` multiply both sides by 4

`4y-16=x-8` add 16 to both sides

`4y=x+8` divide both sides by 4

`y=(1)/(4)x+2`