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1 vote
Fred the clown can create 20 animal balloons every 15 minutes. How much can he create in 6 minutes, and 45 minutes?

2 Answers

7 votes


\bf \textit{\Large in 6 minutes}\\\\ \begin{array}{ccll} balloons&minutes\\ \cline{1-2} 20&15\\ x&6 \end{array}\implies \cfrac{20}{x}=\cfrac{15}{6}\implies 120=15x \\\\\\ \cfrac{120}{15}=x\implies 8=x \\\\[-0.35em] ~\dotfill\\\\ \textit{\Large in 45 minutes}\\\\ \begin{array}{ccll} balloons&minutes\\ \cline{1-2} 20&15\\ x&45 \end{array}\implies \cfrac{20}{x}=\cfrac{15}{45}\implies \cfrac{20}{x}=\cfrac{1}{3}\implies 60=x

User Rexcfnghk
by
5.6k points
4 votes

Answer:



Explanation:

If he creates 20 animal balloons in every 15 minutes, we can reveal the number of the balloons created depending on the given time.

For 6 minutes:

20 balloons in 15 minutes

x balloons in 6 minutes

-> We can conclude that 20(6) = x(15) -> x = 8 balloons

For 45 minutes:

20 balloons in 15 minutes

y balloons in 45 minutes

-> We can conclude that 20(45) = y(15) -> x = 60 balloons

User Kkochanski
by
5.4k points