Answer:
speed of the boat = 29 mph
Explanation:
In order to solve the problem, we need to recall the formula for speed (or velocity "v") of an object as the quotient between the distance (d) covered over the time (t) it takes to cover it:
![v=(d)/(t)](https://img.qammunity.org/2020/formulas/physics/high-school/jidcwnxn1c0zdocnxtzp97sqgn187ivyra.png)
Now we analyse the two different situations (downstream vs upstream) separately:
Downstream:
Considering that when the boat goes downstream (140 mile trip), it goes with the current, so its velocity (unknown v) couples (adds) to that of the current (6 mph) its total speed would be: v + 6 mph. Therefore we can use this information to write the equation for velocity given above, and solve for time:
![v+6=(140)/(t)\\t*(v+6)=140\\t=(140)/(v+6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9ug2w90w33ppsad6srrjg0nzy782zw68ly.png)
Upstream:
In this case, the boat goes against the current, so its speed will be reduced by the current's speed of 6 mph, then its total speed will be: v - 6 mph. Recalling that in this case the boat travels 92 miles in the same time (t) it took it to do the downstream trip, we can write:
![v-6=(92)/(t)\\t*(v-6)=92\\t=(92)/(v-6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/no495ktitrrl5lwnz9shinwp78kaojxut9.png)
Now all we need to do is make these last two equations equal each other since the time used for each trip is the same. We can then solve for the actual speed (unknown v) of the boat:
![(140)/(v+6) = (92)/(v-6) \\140*(v-6)=92*(v+6)\\140v - 840=92v+552\\140v-92v=552+840\\48v=1392\\v=(1392)/(48) =29mph](https://img.qammunity.org/2020/formulas/mathematics/middle-school/orm4unwkw7dds5v4wtovr1z39ehhfa4tga.png)