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1. State the domain and range of the relation shown

in the table. Then determine if it is a function. If
it is a function, determine if it is one-to-one, onto,
both, or neither.

1. State the domain and range of the relation shown in the table. Then determine if-example-1

2 Answers

3 votes

Answer:

Explanation:

Domain is the x value

Range is the y value

If its a function then that means that your x-value only goes to one y-value

If its not a function then that means that your y-value goes to more than one x-value

use those hints to help you answer the question...

User Alex Yeung
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6 votes

Domain: All real numbers

Range: All real numbers

It is a function.

It is neither one-to-one nor onto.

If f(x)=−2x+3:

f(−2)=7

f(4)=−5

f(6)=−9

The domain of a relation refers to the set of all possible input values (x-values), while the range represents the set of all possible output values (y-values). In the given table, the domain consists of all real numbers, and the range includes all real numbers as well. This is because there is a y-value associated with every x-value, and vice versa, indicating that the relation covers the entire real number line.

To determine if the relation is a function, we assess whether each x-value is associated with a unique y-value. In this case, there are no repeated x-values with different y-values, confirming that it is indeed a function.

However, the function is neither one-to-one nor onto. A one-to-one function would mean that each unique x-value maps to a unique y-value, which is not the case here. An onto function would imply that the range covers all possible y-values, but there are missing y-values in this relation.

Next, if f(x)=−2x+3, we can find specific function values:

f(−2)=−2(−2)+3=7

f(4)=−2(4)+3=−5

f(6)=−2(6)+3=−9

These values represent the corresponding y-values for the given x-values in the function.

User AzDesign
by
7.9k points

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