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Solve ∆ PQR Q = 53°, p = 14, q = 14.6

User EOB
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1 Answer

6 votes

Answer:

  • r = 17.8
  • P = 50°
  • R = 77°

Explanation:

The Law of Sines is useful for this. It tells you ...

r/sin(R) = p/sin(P) = q/sin(Q)

First, we can find angle P, then use the sum of angles of a triangle to find angle R. Finally, we can use the ratios again to find the length r.

Solving the equation for P, we get ...

sin(P) = (p/q)sin(Q)

P = arcsin(p/q·sin(Q)) = arcsin(14/14.6·sin(53°)) ≈ 49.98° ≈ 50°

R = 180° -53° -49.98° = 77.02°

Solving the ratios for r gives ...

r = q·sin(R)/sin(Q) = 14.6·sin(77.02°)/sin(53°) ≈ 17.81 ≈ 17.8

The remaining 3 triangle measures are r = 17.8, P = 50°, R = 77°.

Solve ∆ PQR Q = 53°, p = 14, q = 14.6-example-1
User FrengoF
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