Question

AbalI is thrown vertically up Ward with a velocity of 6m/s a,How long doesit takes for the balIt reach the maximum possible height

Answer 1

Step-by-step explanation:

From the normal equation of motion, v=u+at

But in this case, the ball is projected upwards. Therefore we have the final velocity V as 0(at maximum height). Then the acceleration a =g = -9.8m/s^2

v=u+at

0 = 6 + (-9.8)t

0 = 6 - 9.8t

9.8t = 6

t = 6/9.8=0.61s