Answer:
Area swept by minute hand of 14 cm in 5 minutes = 51.33
![\mathrm{cm}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a2tk9dkhgcm2bssrc66cltlv7w1r2fqdhx.png)
Solution:
Given that length of the minute hand = 14 cm
Need to calculate the area swept by minute hand in 5 minutes.
As in 1 hour , that is 60 minutes , minute hand completes a circle .
So area swept by minute hand of 14 cm in 60 minutes = area of circle of radius 14 cm
As area of circle =
![\pi r^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jbq7l9lw0tfwhmngy40fg4vq26fc4vapd0.png)
where r is radius
So area swept by given minute hand in 60 minutes =
![\pi * 14^(2)=(22)/(7) * 14 * 14=616](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ke2iolxccu29wtltsplv5k23rzeorsopju.png)
So area swept by given minute hand in 1 minute =
![(616)/(60)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ewnoa7z272lml4huhv5790on7su6734zd3.png)
And area swept by given minute hand in 5 minute =
![(616)/(60) * 5=51.33](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oq0oh0z7vl5lytmav0hz4xlo1el9szk0x3.png)
Hence area swept by minute hand of 14 cm in 5 minutes is 51.33
![\mathrm{cm}^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a2tk9dkhgcm2bssrc66cltlv7w1r2fqdhx.png)