533,903 views
18 votes
18 votes
The coordinates of the vertices of triangle ABC are A(4,-3), B(2,5), and C(-4,2)? Find the perimeter of triangle ABC to the nearest tenth

User Drew
by
2.9k points

1 Answer

19 votes
19 votes

Answer: 24.4

Explanation:


AB=√((4-2)^2 +(-3-5)^2)=√(4+64)=√(68)\\\\BC=√((2-(-4))^2 +(5-2)^2)=√(6^2 +3^2) =√(45)\\\\AC=√((4-(-4))^2 +(-3-2)^2)=√(64+25)=√(89)\\\\\therefore \text{Perimeter }=√(68)+√(45)+√(89) \approx 24.4

The coordinates of the vertices of triangle ABC are A(4,-3), B(2,5), and C(-4,2)? Find-example-1
User Hesson
by
2.7k points