Question

Elemental analysis of the unknown gas from part a revealed that it is 30.45% n and 69.55% o. What is the molecular formula for this gas?

Answer 1

The answer to your question is: NO₂

Step-by-step explanation:

Data

N = 30.45% = 30.45 g

O = 69.55% = 69.55 g

MW N = 14 g

MW O = 16 g

14 g of N ----------------- 1 mol

30.45 g ---------------- x

x = (30.45 x 1) / 14

x = 2.18 mol of N

16 g of O ---------------- 1 mol

69.55 g ------------------ x

x = (69.55 x 1) / 16

x = 4.35 mol of O

Divide by the lowest number of moles

For N = 2.18 / 2.18 = 1

For O = 4.35 / 2.18 = 1.99 ≈ 2.0

Formula = NO₂