Question

Write the equation 4x − 3y = 12 in the form y = mx + b.

a- y equals start fraction four over three end fraction x minus four
b- y equals start fraction four over three end fraction x minus 12
c- y equals start fraction four over three end fraction x plus four
d- y equals negative start fraction four over three end fraction x minus four

Answer 1

Explanation:

a- y equals start fraction four over three end fraction x minus four

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Answer 2

a is the correct answer y =
`(4)/(3) x - 4`

Explanation:

To write the equation 4x - 3y = 12 in the form y=mx + b, we need to make y subject of the formula in the equation 4x - 3y = 12;

4x - 3y = 12

subtract 4x from both-side of the equation;

4x -4x -3y = 12 - 4x

-3y = 12- 4x

we want to make the left hand side of the equation positive, so we multiply through by a negative sign.

The equation becomes;

3y = -12 + 4x

We can rearrange this equation, hence;

3y = 4x - 12

Divide through by 3

`(3y)/(3) = (4x)/(3) - (12)/(3)`

(On the left hand side of the equation, the 3 numerator will cancel the 3 denominator leaving us with just y, on the right hand side of the equation 3 will divide -12 which will give us -4)

y =
`(4)/(3) x` - 4