Question

A runner starts jogging with an initial velocity of 0.85 m/s and eventually reaches with a final velocity of 5.2 m/s. This change in velocity occurs over a displacement of 12.0 m. What is his acceleration?

Answer 1

The answer to your question is: a = 1.1 m/s²

Step-by-step explanation:

Data

v1 = 0.85 m/s

v2 = 5.2 m/s

displacement = 12.0 m

a = ?

Formula

v2² = v1² + 2ad

a = (v2² - v1²) / 2d

Process

a = (5.2² - 0.85²) / (2)(12)

a = (27.04 - 0.72) / 24

a = 26.32 / 24

a = 1.1 m/s²