Question

What is the hybridization of the central atom in PO(OH)3

Answer 1

Answer : The hybridization of the central atom in
`PO(OH)_3` is,
`sp^3`

Explanation :

Formula used :

`\text{Number of electron pair}=(1)/(2)[V+N-C+A]`

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the given molecule.

The given molecule is,
`PO(OH)_3`

`\text{Number of electrons}=(1)/(2)* [5+3]=4`

The number of electron pair are 4 that means the hybridization will be
`sp^3` and the electronic geometry of the molecule will be tetrahedral.

Hence, the hybridization of the central atom in
`PO(OH)_3` is,
`sp^3`

Answer 2

The hybridizations of the central atom in PO(OH)₃ is sp³.

Step-by-step explanation:

The PO(OH)₃ has the central atom P making one double bond with an oxygen atom and three single bonds with the -OH.

The ligands are arranged in a tetrahedral geometry and the hybridization of the P atom is sp³. The charge is distributed asymetricaly and the molecule is polar.

A representation of the molecule can be seen in the figure attached.