Question

What are the solutions of the quadratic equation? 4x^2+34x+60=0

1) 6, 2/3
2) -5/2, -2/3
3) -6,-5/2
4) -6,4

Answer 1

Option 3) -6,-5/2

Explanation:

we know that

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`4x^(2) +34x+60=0`

so

`a=4\\b=34\\c=60`

substitute in the formula

`x=\frac{-34(+/-)\sqrt{34^(2)-4(4)(60)}} {2(4)}`

`x=\frac{-34(+/-)√(196)} {8}`

`x=\frac{-34(+/-)14} {8}`

`x_1=\frac{-34(+)14} {8}=-(20)/(8)=-(5)/(2)`

`x_2=\frac{-34(-)14} {8}=-6`