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Reparametrize the curve with respect to arc length measured from the point where t = 0 in the direction of increasing t. (Enter your answer in terms of s.) r(t) = 3t i + (7 − 4t) j + (3 + 2t) k

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3 votes

Answer:

The curve is given by r(s)=
3(s)/(√(29))  i + (7 - 4(s)/(√(29)) ) j + (3 + 2(s)/(√(29)) ) k

Explanation:

The aec length of the curve is given by:

L=
\int\limits^t_0  \, dt

r(t) = 3t i + (7 − 4t) j + (3 + 2t) k

r'(t)= 3 i -4 j + 2 k

|r'(t)|=
√(3^2+(-4)^2+2^2) =√(9+16+4) =√(29)

L=
\int\limits^t_0 {√(29)} \, dt=√(29)\int\limits^t_0 \, dt

L=
√(29)t|^t_0=√(29)t-√(29)0=√(29)t

s(t)=
√(29)t

We have to obtain t in terms of s, hence:

t=
(s)/(√(29))

Finally,

r(s)=
3(s)/(√(29))  i + (7 - 4(s)/(√(29)) ) j + (3 + 2(s)/(√(29)) ) k

User David Silveiro
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