Question

On a coordinate plane, a solid straight line has a positive slope and goes through (negative 3, negative 5) and (0, negative 4). Everything to the right of the line is shaded.

Which linear inequality is represented by the graph?

y ≥ One-thirdx – 4
y ≤ One-thirdx – 4
y ≤ One-thirdx + 4
y ≥ One-thirdx + 4

Answer 1

The linear inequality represented by the graph is y ≥ One-thirdx – 4.

Step-by-step explanation:

To find the linear inequality represented by the graph, we need to analyze the slope and the shaded area on the coordinate plane. Since the line has a positive slope and everything to the right of the line is shaded, we can conclude that the line represents the inequality y ≥ One-thirdx – 4.

Answer 2

y ≤ One-thirdx – 4

Step-by-step explanation:

The key hint to know this answer is to understand that the line cuts the y-axis at -4. And, we can know that y is less than or equal to (≤) 1/3x-4 for the shaded area to the RIGHT of the line, telling us that y exists for all values from -4 and under.