Question

1. The sides of a triangle have lengths of 5, 8, and 6.(1/ 2). An angle bisector meets the side of length 6.(1/ 2). Find the lengths x and y.

Answer 1

Explanation:

i assume x+y=6(1/2)=\frac{13}{2}

`(5)/(8)=(x)/(y)=(x)/((13)/(2)-x)=(2x)/(13-2x)\\65-10x=16x \\26 x=65\\2x=5\\x=(5)/(2)\\y=(13)/(2)-(5)/(2)=(8)/(2)=4`