Question

Combining 0.236 mol Fe2O3 with excess carbon produced 16.4 g Fe. Fe2O3 3C⟶2Fe 3CO What is the actual yield of iron in moles

Answer 1

The actual yield of iron in moles is 0.293 mol.

Step-by-step explanation:

The actual yield of iron in moles can be calculated by using the information provided in the balanced chemical equation and the given mass of iron produced. According to the balanced equation, 1 mol of Fe2O3 reacts with 3 mol of C to produce 2 mol of Fe. Given that 16.4 g of Fe is produced, we need to convert this mass to moles of Fe. Using the molar mass of Fe (55.85 g/mol), we can calculate:

16.4 g Fe × (1 mol Fe / 55.85 g Fe) = 0.293 mol Fe

Therefore, the actual yield of iron in moles is 0.293 mol.

Answer 2

The actual yield of iron = 0.294 moles

Step-by-step explanation:

Step 1: The balanced reaction

Fe2O3 +3C → 2Fe + 3CO

For 1 mole of Fe2O3 consumed, there is needed 3moles of Carbon to produce 2 moles of Fe and 3 moles of CO

Step 2: Calculate moles of Fe

Moles of iron = mass of iron / Molar mass of iron

moles of iron = 16.4 g / 55.845g/mole = 0.294 mole

The actual yield of iron = 0.294 mole

Step 3: Fe2O3 is the limiting reactant, this means the 0.236 moles will completely react.

1 mole of Fe2O3 consumed, will produce 2 moles of Fe

This means 0.236 moles of Fe2O3 will produce 2*0.236 = 0.472 moles of Fe. This is the theoretical yield of iron.

The percentage yield = 0.294/0.472 * 100% = 62.29 %

The actual yield of iron = 0.294 moles