Final answer:
The object with initial velocity of 25 m/s and a constant acceleration of -1.5 m/s² travels 106.25 meters in 5.0 seconds.
Step-by-step explanation:
To calculate the distance an object travels under constant acceleration, we can use the kinematic equation for displacement, which is:
s = ut + ½at²
Where s is the displacement, u is the initial velocity, a is the acceleration, and t is the time. Given that the initial velocity (u) is 25 m/s, the acceleration (a) is -1.5 m/s², and the time (t) is 5.0 seconds, we can plug these values into the equation:
s = (25 m/s)(5.0 s) + ½(-1.5 m/s²)(5.0 s)²
s = 125 m - ½(1.5 m/s²)(25 s²)
s = 125 m - 18.75 m
s = 106.25 meters
Therefore, the object travels 106.25 meters in 5.0 seconds.