Question

A ball is thrown straight upward at 17 m/s.

a) How long does it take to reach its highest point?

Answer 1

≈ 1.7346s

Step-by-step explanation:

Because we are trying to find when it is at it's highest point we can safely say that it's velocity at that point is 0m/s,

therefore we can use the equation:

`v_f = a(t_t) + v_i`

and do some algebra to get:

`(v_f - v_i)/(a) = t_t`

Now we plug in our values (note that this is assumed to be on Earth and that because it says that upwards is positive, we set g to be negative to say that it is pointing down):

`(0m/s - 17m/s)/(-g) = t_t`

=

`(-17m/s)/(-9.8m/s^2) = t_t`

=

`(17)/(9.8s) = t_t`

≈

`1.7346s \approx t_t`