Answer:
The ratio will be different
Step-by-step explanation:
- The ratio of cation to anion when group 2A cations form ionic compounds with anions of group 7A will be 1: 2.
- Group 2A elements have a valency of two and react by losing two electrons forming a cation with a charge of +2. Examples of group 2A cations include Ca²⁺, Mg²⁺ , and Ba²⁺ among others.
- Group 7A elements have a valency of one and react by gaining one electron forming an anion with a charge of -1. Examples of group 7A anions are Cl⁻, Br⁻ , and F⁻ among others.
- Group 2A elements react with group 7A elements to form an ionic compound. For example;
Ca(s) + Cl₂(g) → CaCl₂(aq)
- The ionic compound contains 1 Ca²⁺ cation and 2 Cl⁻ anions, thus the ratio of cations to anion in the compound is 1:2.