Question 1:
For this case we have that by definition, the point-slope equation of a line is given by:

Where:
m: It's the slope
It is a point through which the line passes

Thus, the equation is of the form:

We make a point:

Finally, the equation is:

ANswer:

Question 2:
For this case we have the following comparison, after one week:
Plant 1:
(3 was the initial height)
Plant 2:
(3 was the initial height)
It is observed that in one week each plant grew 1.3 inches.
Thus, the statement that best compares this situation is:

Answer:
Option C