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Two identical 9.10-g metal spheres (small enough to be treated as particles) are hung from separate 300-mm strings attached to the same nail in a ceiling. Surplus electrons are added to each sphere, and then the spheres are brought in contact with each other and released. Their equilibrium position is such that each string makes a 13.0 ∘ angle with the vertical. How many surplus electrons are on each sphere?

User Ideaztech
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1 Answer

2 votes

Answer:


n = 1.266* 10^(12)

Step-by-step explanation:

Given data:

mass of sphere is 10 g

Angle between string and vertical axis is
\theta = 13 degree

thickness of string 300 mm = 0.3 m


sin\theta =(2)/(0.3 m)

r =0.3 sin 13 = 0.067 m


Fe = ( kq_1 q-2)/(d^2)


Fe = (kq^2)/((2r)^2) = mg tan\theta


q^2 =  mg tan\theta ((2r)^2)/(k)


= 0.0091 * 9.8 tan13 * ((2* 0.067)^2)/(9* 10^9)


q^2 = 4.10* 10^(-14)


q = 2.026 * 10^(-7) C

q = ne


n = (1.6* 10^(-19))/(2.02* 10^(-7))


n = 1.266* 10^(12)

User Gpampara
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