Question

One cubic meter of nitrogen at 40°C and 340kPa is compressed isoentropically to 0.2m^3. Calculate the final pressure when the nitrogen is reduced to that volume. What is the modulus of elasticity at the beginning and end of the compression? (k = 1.4)

Answer 1

a)P₂=3236.21 KPa

b)E=3620.26 KPa

Step-by-step explanation:

Given that

V₁= 1 m³

T₁=40°C

P₁= 340 KPa

V₂=0.2 m³

k= 1.4

We know that for isentropic process

`PV^(k)=C`

`P_1V_1^(k)=P_2V_2^(k)`

`340* 1^(1.4)=P_2* 0.2^(1.4)`

P₂=3236.21 KPa

Final pressure of gas P₂=3236.21 KPa

We know that modulus of elasticity

`E=(dP)/(-(dV)/(V))`

`E=(3236.21-340)/(-(0.2-1)/(1))`

E=3620.26 KPa