Question

A bike is traveling to the left with the speed of 27 m/s when the rider slams on the brakes. The bike skids for 41.5 m with the constant acceleration before it comes to a stop.

What was the acceleration of the bike as it cane to a stop?

Answer 1

The acceleration of the bike is equal to
`8.78(m)/(s^(2))` opposing the movement (to the right).

Why?

Since after the rider slams the brakes, the bike came to a stop, we know that the acceleration is opposite to the velocity/movement.

We can use the following equation to calculate the acceleration:

`v_(f)^(2)=v_(o)^(2)+2*a*d`

So, substituting, we have: (let's consider negative to the left and positive to the right)

`0=(-27(m)/(s) )^(2)+2*a*41.5m\\\\0=729(m^(2) )/(s^(2) )+83*a\\\\a=(-729(m^(2))/(s^(2)))/(83m)=-8.78(m)/(s^(2))`

The negative sign means that the acceleration's direction is opposite to the movement.

Hence, we have that the acceleration is equal to
`8.78(m)/(s^(2))` opposing the movement (to the right).

Have a nice day!

Answer 2

Answer: 8.78

Step-by-step explanation: