Question

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats facing the axis, their backs against the outer wall. At one instant the outer wall moves at a speed of 3.44 m/s, and an 64.8-kg person feels a 261-N force pressing against his back. What is the radius of a chamber?

Answer 1

r = 2.93 m

Step-by-step explanation:

mass of the person = 64.8 kg

speed v = 3.44 m/s

Force F = 261 N

using formula

`F = (mv^2)/(r)`

the radius of the chamber is given by

`r = (mv^2)/(F)`

`r = (64.8* 3.44^2)/(261)`

r = 2.93 m

so, the radius of a chamber is equal to 2.93 m