Question

A refrigeration cycle has QH= 1700 Btu and Wcycle = 300 Btu. Determine: a. the coefficient of performance for the refrigeration cycle b. the coefficient of performance if the cycle is used as a heat pump

Answer 1

COP=Refrigeration Cycle=4.67

COP=heat pump=5.67

Step-by-step explanation:

Hello!

To solve this problem we must consider the following

There are three related energy flows for these types of problems:

Qh = heat rejected,

Wcycle = the electrical power entering the compressor.

Qo = heat entering

if we apply the principle of conservation of energy we can find Qo

Qo+Wcycle=Qh

Qo=Qh-Wcycle

Qo=Qh-Wcycle

Qo=1700-300=1400BTU

We now remember that for a refrigerator the operational coefficient COP is the ratio between the heat entering the Qo system, and the power supplied.

`COP=(Qo)/(Wcycle) =(1400)/(300) =4.67`

We now remember that for a heat pump the operational coefficient COP is the ratio between the heat that rejected Qh, and the power supplied.

`COP=(Qh)/(Wcycle) =(1700)/(300) =5.67`