Question

Determine linear atomic density along [001] direction of a FCC unit cell with lattice constant a (cube edge length).

Answer 1

`LD=(0.5)/( a)`

Step-by-step explanation:

Given that

Unit cell is in FCC

Here given direction is not clear visible so we take direction [001].

We know that linear density(LD) given as

`LD=(Number\ of\ atoms\ in\ the\ direction\ vector)/(d_([001]))`

So the number of atom will be 1/2 in direction [001]

In FCC

`a=2\sqrt2 \ r`

`LD=(0.5)/( a)`

`LD=(1)/(2\sqrt2 \ r)`