Question

2. A roller coaster at an amusement park has a dip that bottoms out in a vertical circle of radius r. A passenger feels the seat of the car pushing upward on her with a force equal to five times her weight as she goes through the dip. Of r = 21.5 m, how fast is the roller coaster traveling at the bottom of the dip?

Answer 1

Answer:
`v=√(4gr)`

Step-by-step explanation:

Given

Passenger feels the seat of the car Pushing upward with a force equal to five times her weight

Therefore

`N-mg=(mv^2)/(r)`

it is given
`N=5mg`

where N=normal reaction

`5mg-mg=(mv^2)/(r)`

thus
`v=√(4gr)`