Question

A 650 kg airplane must reach its takeoff speed while traveling down a 61.0 m long runway. The pilot starts the plane from rest, and by the end of the runway he has reached the takeoff speed of 29.0 m/s. To the nearest newton, what net force must act on the plane? Hint: there are multiple ways you could go about solving this problem.

Answer 1

Explanati2/7 = 8/28

1/4 = 7/28

Therefore Mr Pham mowed more.

8+7 = 15 so 15/28 of lawn has been mowed, therefore 13/28 of the lawn is left still to be mowe.

on:

Answer 2

Force in the plane will be 4488.09 N

Step-by-step explanation:

We have given mass of the airplane m = 650 kg

Length of the runway S = 61 m

As the plane starts from rest so initial; velocity u = 0 m/sec

Final velocity of airplane v = 29 m/sec

From first equation of motion v = u+at

29 = 0+at

at = 29

From second equation of motion
`s=ut+(1)/(2)at^2`

`61=0* t+(1)/(2)at^2`

`122=at^2`

Now using at =29

`122=29t`

t = 4.20 sec

So
`4.2a=29`

`a=6.9m/sec^2`

According to second law of motion F= ma

So force F = 650×6.9 = 4488.09 N