Question

A balloon filled with an ideal gas initially has a temperature of 24°C and a volume of 7.0 L. If the gas in the balloon is heated to 104°C while the pressure in the balloon is held constant, what volume will the balloon expand to? Round to the nearest tenth of a liter. Hint: remember to use the appropriate temperature scale!

Answer 1

8.9L

Step-by-step explanation:

`\\ Using\quad Charles'\quad Law\\ \\ \frac { { V }_( 1 ) }{ { T }_( 1 ) } =\quad \frac { { V }_( 2 ) }{ { T }_( 2 ) } \\ provided\quad the\quad pressure\quad of\quad the\quad gas\quad is\quad kept\quad constant.\\ Temperature\quad should\quad be\quad in\quad Kelvins:\quad \\ Kelvin\quad Temperature\quad =\quad Celsius\quad Temperature\quad +\quad 273.15\quad \\ Given\quad information:\\ { V }_( 1 )=\quad 7L\quad \quad \quad \quad \quad \quad { V }_( 2)\quad is\quad unknown\quad \quad {T}_( 1 )=\quad 24+273.15=297.5K\quad \quad \quad { T }_( 2 )=104+273.15=377,15K\\ \therefore \quad \frac { 7L }{ 297.5K } =\frac { { V }_( 2 ) }{ 377.5K } \\ \quad \quad \quad 2640.05\quad =\quad 297.5{ V }_( 2 )\\ \quad \quad \quad \quad \quad \quad \quad \quad { V }_(2)=\frac { 2640.05 }{ 297.5 } \quad \\ \quad \quad \quad \quad \quad \quad \quad \quad { V }_( 2 )=8.9\quad L\quad to\quad the\quad nearest\quad tenth\quad of\quad a\quad liter.`