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Is the point P (2,8) on the inside or outside of the circle described with equation x^2+y^2=100?

User Ruffsl
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1 Answer

5 votes

Points
(x,y) on the circle satisfy
x^2+y^2=100.

Points inside the circle satisfy
x^2+y^2<100.

Points outside the circle satisfy
x^2+y^2>100.

We have


2^2+8^2=4+64=68<100

so the point (2, 8) lies inside the circle.

User Darren Shewry
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