Question

The spectrum of a blackbody has a peak wavelength of 2.80×10-7 meters. What is its temperature, in kelvins?

Answer 1

Answer:
`1.03* 10^4K`

Step-by-step explanation:

Using Weins displacement law:

`\lambda _(max)=(b)/(T)`

where
`\lambda _(max)` = wavelength =
`2.80* 10^(-7)m`

b = constant =
`2.897* 10^(-3)mK`

T = Temperature in Kelvin = ?

Putting the values we get:

`2.80* 10^(-7)m=(2.897* 10^(-3)mK)/(T)`

`T=1.03* 10^4K`

Thus the temperature of the blackbody will be
`1.03* 10^4K`