Question

The first step of the EMP and ED pathways of glucose catabolism that converts glucose into glucose 6-phosphate had a ΔGo' of 14.3kJ/mol. It is coupled with the hydrolysis of ATP to ADP, which has a ΔGo' of –31kJ/mol. What is the ΔGo' of the coupled reaction?

Answer 1

`\Delta Go` for couple reaction is -16.7 kJ/mol

Step-by-step explanation:

Given data:

`\Delta Go' =14.3 kJ/mol` for glucose conversion to glucose 6 phosphate

`ATP = ADP + \Delta GO' IS GIVEN AS -31 kJ/mol`

from above data we have following reaction

Glucose = Glucose 6 phosphate
`\Delta Go' of 14.3 kJ/mol`

`ATP = ADP + \Delta Go' \ of -31 kJ/mol`

when coupling both reaction we have

Glucose + ATP = Glucose 6 phosphate + ADP

`\Delta Go' of 14.3 + \Delta Go'  of -31 kJ/mol = -16.7 kJ/mol`

therefore
`\Delta Go` for couple reaction is -16.7 kJ/mol