Question

5. The table shows the total vertical distance a free-falling body travels for each second it falls. About how far does the free-falling body travel between 4 and 5 seconds? a. 44 m b. 54 m c. 144 m d. 154 m

Answer 1

a. 44 m

Step-by-step explanation:

We don't have the table but we can still answer since the motion is a free-fall motion.

First of all, we calculate the velocity of the body at time t = 4 s, with the equation

`u'=u+gt`

where

u = 0 is the initial velocity

g = 9.8 m/s^2 is the acceleration of gravity (we take downward as positive direction)

t is the time

Using t = 4 s,

`u'=0+(9.8)(4)=39.2 m/s`

Now we can calculate the distance covered during the time t = 4 s and t = 5 s using the other suvat equation

`s=u'\Delta t+(1)/(2)g\Delta t^2`

where

`\Delta t = 5-4=1s` is the time interval we are considering. Substituting values,

`s=(39.2)(1)+(1)/(2)(9.8)(1)^2=44 m`