219k views
4 votes
A bird watcher spots a sparrow in a tree. The sparrow sits in a nest that is 10.5 feet above the bird watcher's eye level, at a 35° angle of elevation from the bird watcher. The bird watcher then notices a hawk in the same tree, 7.4 feet above the sparrow, at a certain angle of elevation. The bird watcher stands 15 feet from the base of the tree. What is the angle of elevation from the bird watcher to the hawk?

User Amit Bisht
by
7.9k points

1 Answer

5 votes

Answer:

the angle is 50 degrees.

Step-by-step explanation:

To solve this trigonometric problem we need ot remember that:


\alpha=arctg((O)/(A))

where O is the opposite side of the triangle and A the adjacent

The hawk is 7.4 feet above the sparrow so:


O=10.5+7.4\\O=17.9ft


\alpha =arctg((17.9)/(15))=50^o

User Pye
by
8.8k points