Question

How fast (in rpm) must a centrifuge rotate if a particle 5.50 cm from the axis of rotation is to experience an acceleration of 119000 g's? If the answer has 4 digits or more, enter it without commas, e.g. 13500.

Answer 1

The velocity angular must be:

`w=43994rpm`

Step-by-step explanation:

The definition of the centripetal acceleration is:

`a_c=w^2*r`

where, w, is the angular velocity

we solve in order to find w:

`w=√(a_c/r)=√(119000*g/0.055)=√(119000*9.81/0.055)=4607rad/s\\w=4607rad/s*(1 revolution/(2\pi*rad))*(60s/1mn)=43994rpm`