Question

A rifle is aimed horizontally at a target 30 m away. The bullet hits the target 1.9 cm below the aiming point. What are the bullet’s a. time of flight? b. speed as it emerges from the rifle? 3.

Answer 1

Answer:0.0622 s

482.31 m/s

Step-by-step explanation:

Given

target distance=30 m

Bullet hits the target 1.9 cm below

If we consider bullet motion to be projectile then

vertical distance traveled=1.9 cm

time travel to cover 1.9 cm is

`h=ut+(at^2)/(2)`

here u is initial vertical velocity

`1.9* 10^(-2)=0+(9.8* t^2)/(2)`

`t^2=0.3877* 10^(-2)`

`t=0.622* 10^(-1)=0.0622 s`

Range =30 m

`30=u_x* t`

`30=u_x* 0.0622`

`u_x=482.31 m/s`