Question

State how many imaginary and real zeros the function has.

f(x) = x3 + 5x2 + x + 5

Answer 1

answer above

Explanation:

trust me

Answer 2

Explanation:

f(x) = x³ + 5x² + x + 5

f(x) = x² (x + 5) + x + 5

f(x) = (x² + 1) (x + 5)

The function has one real root (x = -5) and two imaginary roots (x = ±i).