Question

One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching this first snowball, you throw a second snowball at a low angle and time it to arrive at the same time as the first. Assume both snowballs are thrown with the same initial speed 29.3 m/s. The first snowball is thrown at an angle of 63◦ above the horizontal. At what angle should you throw the second snowball to make it hit the same point as the first? The acceleration of gravity is 9.8 m/s 2 . Answer in units of ◦ .

Answer 1

Answer:
`27^(\circ)`

Step-by-step explanation:

Given

Initial velocity of both snowball is 29.3 m/s

first snowball launch angle
`=63^(\circ)`

Considering motion of snowball to be projectile

range is given by

`R=(u^2\sin 2\theta )/(g)`

`R=(29.3^2\sin 126)/(9.8)`

R=70.87 m-----1

If second snowball is thrown at an angle of \phi

`R=(u^2\sin 2\phi )/(g)`

`R=(29.3^2\sin 2\phi )/(9.8)`------2

`70.87=87.601\sin 2\phi`

`0.809=\sin \phi`

`2\phi can be 53.99^(\circ)`

or
`180-2\phi =53.99^(\circ)`

Thus
`\phi =26.995 \approx 27^(\circ)`