Answer:
Option B.
Explanation:
Cost of game = $5.00
If they draw a face card, they win $10.00 (i.e. they get their $5.00 back and get an extra $5.00).
Winning amount = $5
Number of face cards = 12
Probability of getting a face card =

If they draw an ace, they win $20.00 (i.e. they get their $5.00 back and get an extra $15.00).
Winning amount = $15
Number of ace = 4
Probability of getting an ace =

Any other draw they lose their money.
Number of other card (Exclude ace and face cards) = 52-4-12=36
Probability of getting other cards =

The expected money value playing this game is
E(x) = 5 × P(face cards) + 15 × P(Ace) - 5 × P(Other cards)





The expected money value playing this game is -$1.15
Therefore, the correct option is B.